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	<title>Comments on: 888</title>
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	<link>http://disinformatics.com/blog/2008/02/24/888/</link>
	<description>anguish and delusion...</description>
	<pubDate>Mon, 01 Dec 2008 22:29:14 +0000</pubDate>
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		<item>
		<title>By: Farhan Mannan</title>
		<link>http://disinformatics.com/blog/2008/02/24/888/#comment-243</link>
		<dc:creator>Farhan Mannan</dc:creator>
		<pubDate>Mon, 25 Feb 2008 23:31:52 +0000</pubDate>
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		<description>Jigga shit. I couldn't do a new factorisation but I made an expression for abc basically subbing in ab = a and c = b (you know?) into the other one, but with ab as the expanded jigga. So it's some recursive biotch. It comes out to the retard image I just put on the end of that thing.</description>
		<content:encoded><![CDATA[<p>Jigga shit. I couldn&#8217;t do a new factorisation but I made an expression for abc basically subbing in ab = a and c = b (you know?) into the other one, but with ab as the expanded jigga. So it&#8217;s some recursive biotch. It comes out to the retard image I just put on the end of that thing.</p>
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	<item>
		<title>By: Elliot</title>
		<link>http://disinformatics.com/blog/2008/02/24/888/#comment-242</link>
		<dc:creator>Elliot</dc:creator>
		<pubDate>Mon, 25 Feb 2008 21:05:50 +0000</pubDate>
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		<description>You still have one modulus that shouldn't be there, it should be a square, so difference of two squares gives ((a+b)/2-(a+b)/2+a)((a+b)/2+(a+b)/2-a) = (a)(b).</description>
		<content:encoded><![CDATA[<p>You still have one modulus that shouldn&#8217;t be there, it should be a square, so difference of two squares gives ((a+b)/2-(a+b)/2+a)((a+b)/2+(a+b)/2-a) = (a)(b).</p>
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	<item>
		<title>By: Farhan Mannan</title>
		<link>http://disinformatics.com/blog/2008/02/24/888/#comment-240</link>
		<dc:creator>Farhan Mannan</dc:creator>
		<pubDate>Mon, 25 Feb 2008 20:49:44 +0000</pubDate>
		<guid isPermaLink="false">http://disinformatics.com/blog/2008/02/24/888/#comment-240</guid>
		<description>lulz i am a jam donut</description>
		<content:encoded><![CDATA[<p>lulz i am a jam donut</p>
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	<item>
		<title>By: Elliot</title>
		<link>http://disinformatics.com/blog/2008/02/24/888/#comment-239</link>
		<dc:creator>Elliot</dc:creator>
		<pubDate>Mon, 25 Feb 2008 20:47:36 +0000</pubDate>
		<guid isPermaLink="false">http://disinformatics.com/blog/2008/02/24/888/#comment-239</guid>
		<description>You don't need the modulus when you just square it afterwards. otherwise cool.</description>
		<content:encoded><![CDATA[<p>You don&#8217;t need the modulus when you just square it afterwards. otherwise cool.</p>
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